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PythonPython Tutorial
Lesson

Python For Loops

10 min reading
Free Course

Python For Loops: Clean Iteration with range(), enumerate(), and zip()

A Python for loop iterates directly over each item in a sequence or iterable such as a list, string, tuple, set, dictionary, or file. You never have to initialize i = 0 or increment index counters manually.

When you also need the numeric position or want to walk two lists side by side, Python's built-in enumerate() and zip() helpers keep your loop body clean.

Using range(), enumerate(), and zip()

range(start, stop, step) generates numbers lazily without storing a huge list in memory. enumerate(items, start=1) yields (index, value) pairs cleanly.

servers = ["web-01", "web-02", "db-01"]
cpu_loads = [42, 68, 31]

for idx, (server, load) in enumerate(zip(servers, cpu_loads), start=1):
    status = "HIGH" if load > 60 else "OK"
    print(f"{idx}. {server}: {load}% ({status})")

Breaking Early and for ... else

Just like while, break exits a for loop early, and continue jumps to the next item. A trailing else: runs only if the loop finished without hitting break, which is handy for search loops.

for n in [4, 6, 8, 9]:
    if n % 2 != 0:
        print(f"Found odd number: {n}")
        break
else:
    print("All numbers were even")

Common Mistakes to Avoid

  • Looping with for i in range(len(items)):: Iterate directly with for item in items: or enumerate(items) unless you are overwriting indices in place.
  • Expecting range(1, 5) to include 5: range stops before the end argument, yielding 1, 2, 3, 4.
  • Unbalanced zip() lengths: By default zip() stops at the shortest iterable; pass strict=True in Python 3.10+ to catch mismatched lengths.

Frequently Asked Questions

Can I loop backward over a list?

Yes. Wrap the sequence in reversed(items), which iterates in reverse without copying the list.

How do I loop over a dictionary's keys and values?

Call for key, value in my_dict.items(): to unpack both parts on each iteration.

Does range(1_000_000) use lots of memory?

No. range computes each number on demand, using the same tiny memory regardless of how large the range is.

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